document.write( "Question 995708: Help is urgently needed.\r
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document.write( "The profit P(in millions of pesos) for a manufacturer of tablets can be modeled by where x is the number of tablets produced (in millions). Currently, the company produces 3 million tablets and makes a profit of 48,000,000 pesos. What lesser number of tablets could the company produce and still make the same profit? \n" );
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Algebra.Com's Answer #614388 by Theo(13342)![]() ![]() You can put this solution on YOUR website! to find out the point where profit is equal to 0, just set the equation equal to 0 and solve.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-4x^3 + 12x^2 + 16x = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor out the gcf to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-4x) * (x^2 - 3x - 4) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor x^2 - 3x - 4 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-4x) * (x-4) * (x+1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "set each of these factors equal to 0 and solve for x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 0, x = 4, x = -1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x represents number of tablets.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 0 leads to a profit of 0 but that's trivial. \n" ); document.write( "x = -1 is invalid because number of tablets can't be negative. \n" ); document.write( "only valid answer is that profit is 0 when x = 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have 3 zero crossing points and you want to see whether profit is positive or negative between them.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the only intervals that are valid are the intervals between x = 0 and x = 4, and the interval where x is greater than 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it turns out that x is positive in the interval between x = 0 and x = 4 only.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it is negative otherwise.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you look at the graph, you will see that the same profit is made when x = 2 and when x = 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that can be seen by drawing a horizontal line at y = 48 and the intersection will be at x = 2 and x = 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the grpah of your equation is shown below along with the line of y = 48.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "results on the graph are in millions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 2 million, you make a 48 million profit. \n" ); document.write( "when x = 3 million, you make a 48 million profit.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |