document.write( "Question 995689: A park has a permiter of 140. If the length of the park is 20meters more than its width.,what is the are?\r
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Algebra.Com's Answer #614376 by phillywily(18)\"\" \"About 
You can put this solution on YOUR website!
Take width as x, and since length is 20 longer than width, length should be (x+20).
\n" ); document.write( "Perimeter=140
\n" ); document.write( "140=2(x+20)+2x
\n" ); document.write( "140=2x+40+2x
\n" ); document.write( "140=4x+40
\n" ); document.write( "140-40=4x
\n" ); document.write( "100=4x
\n" ); document.write( "x=25
\n" ); document.write( "Width=25
\n" ); document.write( "Length
\n" ); document.write( "=25+20
\n" ); document.write( "=45
\n" ); document.write( "Area
\n" ); document.write( "=Width×Length
\n" ); document.write( "=25(45)
\n" ); document.write( "=1125m²\r
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