document.write( "Question 995567: Length of a rectangle is 5 cm less then twice its breadth, if the length is decreased by 3 cm and breadth increased by 2 cm the perimetre is 72. find the area of original rectangle. \n" ); document.write( "
Algebra.Com's Answer #614344 by ankor@dixie-net.com(22740)\"\" \"About 
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Let L & W be the original length and width
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\n" ); document.write( "Write an equation for each statement.
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\n" ); document.write( " Length of a rectangle is 5 cm less then twice its breadth,
\n" ); document.write( "L = 2W - 5
\n" ); document.write( " if the length is decreased by 3 cm and breadth increased by 2 cm the perimeter is 72.
\n" ); document.write( "2(L-3) + 2(W+2) = 72
\n" ); document.write( "Divide equation by 2
\n" ); document.write( "L - 3 + W + 2 = 36
\n" ); document.write( "L + W - 1 = 36
\n" ); document.write( "L + W = 37
\n" ); document.write( "Replace L with (2W-5)
\n" ); document.write( "(2W-5) + W = 37
\n" ); document.write( "3W = 37 + 5
\n" ); document.write( "3W = 42
\n" ); document.write( "W = 42/3
\n" ); document.write( "W = 14 cm is the original width
\n" ); document.write( "Find L
\n" ); document.write( "L = 2(14) - 5
\n" ); document.write( "L = 28 - 5
\n" ); document.write( "L = 23 cm is the original length
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\n" ); document.write( "find the area of original rectangle.
\n" ); document.write( "23 * 14 = 322 sq cm
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