document.write( "Question 995562: a garrison of 600 men had provision for 25 days.after 9 days an addition of men was made and the remaining provision latest only for 4 days.find the number added. \n" ); document.write( "
Algebra.Com's Answer #614329 by MathTherapy(10551)\"\" \"About 
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\n" ); document.write( "a garrison of 600 men had provision for 25 days.after 9 days an addition of men was made and the remaining provision latest only for 4 days.find the number added.
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\"M+=+k%28c%29%2FT\", with:\r\n" );
document.write( "M being number of men\r\n" );
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document.write( "k being constant of variation\r\n" );
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document.write( "c being consumption\r\n" );
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document.write( "T being time\r\n" );
document.write( "\"600+=+k%281%29%2F25\"\r\n" );
document.write( "\"600+=+k%2F25\"\r\n" );
document.write( "\"k+=+600%2825%29\", or 15,000\r\n" );
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document.write( "In 9 days, we get:\r\n" );
document.write( "\"M+=+k%28c%29%2FT\"\r\n" );
document.write( "\"600+=+15000%28c%29%2F9\"\r\n" );
document.write( "\"600+=+15000c%2F9\"\r\n" );
document.write( "\"15000c+=+600%289%29\"\r\n" );
document.write( "c, or fraction consumed in 9 days = \"600%289%29%2F15000\", or \"9%2F25+\"\r\n" );
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document.write( "In 9 days, \"9%2F25\" of the provision was consumed by 600 men, so \"1+-+9%2F25\", or \"16%2F25\" of provision remain\r\n" );
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document.write( "With additional men being A, we get:\r\n" );
document.write( "\"M+%2B+A+=+k%28c%29%2FT\"\r\n" );
document.write( "\"600+%2B+A+=+15000%2816%2F25%29%2F4\"\r\n" );
document.write( "\"600+%2B+A+=+600%2816%29%2F4\"\r\n" );
document.write( "600 + A = 2,400\r\n" );
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document.write( "A, or additional men = 2,400 - 600, or \"highlight_green%281800%29\"
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