document.write( "Question 995562: a garrison of 600 men had provision for 25 days.after 9 days an addition of men was made and the remaining provision latest only for 4 days.find the number added. \n" ); document.write( "

Algebra.Com's Answer #614328 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
In 1 day, the 600 men consume $\"+1%2F25+\"$
\n" ); document.write( "of the provisions
\n" ); document.write( "----------------
\n" ); document.write( "In 1 day, each of the 600 men consume
\n" ); document.write( " $\"+%28+1%2F600+%29%2A%28+1%2F25+%29+=+1%2F15000+\"$ of the
\n" ); document.write( "provisions
\n" ); document.write( "----------------
\n" ); document.write( "After 9 days, the 600 men consume $\"+9%2F25+\"$
\n" ); document.write( "of the provisions
\n" ); document.write( "That means there is $\"+1+-+9%2F25+=+16%2F25+\"$
\n" ); document.write( "of the provisions left
\n" ); document.write( "-----------------
\n" ); document.write( " $\"+16%2F25+\"$ was consumed in 4 days
\n" ); document.write( "[ rate for 1 man in 1 day ] x [ 600 + n men] x [ 4 days ] = [ fraction of provisions left ]
\n" ); document.write( " $\"+%28+1%2F15000+%29%2A4%2A%28+600+%2B+n+%29+=+16%2F25+\"$
\n" ); document.write( " $\"+4%2A%28+600+%2B+n+%29+=+%28+16%2F25+%29%2A15000+\"$
\n" ); document.write( " $\"+600+%2B+n+=+%28+4%2F25+%29%2A15000+\"$
\n" ); document.write( " $\"+n+=+2400+-+600+\"$
\n" ); document.write( " $\"+n+=+1800+\"$
\n" ); document.write( "1800 men were added
\n" ); document.write( "-------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+1800+%2B+600+=+2400+\"$
\n" ); document.write( " $\"+%28+1%2F15000+%29%2A4%2A2400+=+.64+\"$
\n" ); document.write( " $\"+16%2F25+=+.64+\"$
\n" ); document.write( "OK
\n" ); document.write( "Definitely get a 2nd opinion on this.
\n" ); document.write( "It is a little tricky for me\r
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