document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995565>Question 995565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Good Morning. I am trying to figure out how to complete the square for this problem but I am having no luck My problem is:<BR>\n" );
document.write( "3x^2-13x+4=0. I know I have to divide each term by 3 which would give me:\r<BR>\n" );
document.write( "\n" );
document.write( "x^2-13/3x+4/3=0. Then I subtract 4/3 on both sides to get x^2-13/3x=-4/3. I multiply -13/3xand 1/2 to get -13/6x then I square it to get 169/36 which I add to both sides of the equation. <BR>\n" );
document.write( "x^2-13/3x+169/36=-4/3+169/36. Here is where I'm having a hard time and are looking for your help.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614313 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x²-13x+4=0<BR>\n" );
document.write( "x²-13x/3+4/3=0<BR>\n" );
document.write( "x²-13x/3=-4/3<BR>\n" );
document.write( "take the half of 13/3,square it,then add it to bothside<BR>\n" );
document.write( "From the above,half of 13/3 is 26/3 then it's square is 676/9,Then add 676/9 in bothside of the equation,<BR>\n" );
document.write( "x²-13x/3+676/9=676/9-4/3<BR>\n" );
document.write( "(x-26/3)²=(676-12)/9<BR>\n" );
document.write( "(x-26/3)²=664/9<BR>\n" );
document.write( "solve it from here!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );