document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995584>Question 995584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measures of two complementary angles if one angle is 18 degrees more than 3 times another angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614303 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let a and b be the comp angles.<BR>\n" );
document.write( "From your question,<BR>\n" );
document.write( "a+b=90---(1)(complementary angles sum up to 90)<BR>\n" );
document.write( "a=3b+18---(2)<BR>\n" );
document.write( "put 2 in 1<BR>\n" );
document.write( "3b+18+b=90<BR>\n" );
document.write( "4b=90-18<BR>\n" );
document.write( "4b=72<BR>\n" );
document.write( "b=18<BR>\n" );
document.write( "put b=18 in 2<BR>\n" );
document.write( "a=3(18)+18<BR>\n" );
document.write( "a=72<BR>\n" );
document.write( "The measure of the angles are 18degree and 72degree </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );