document.write( "Question 995514: Suppose f(x)=ax^4+bx^2+x+5, where a and b are constants. Find f(4) if f(-4)=3 \n" ); document.write( "
Algebra.Com's Answer #614259 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "Suppose f(x)=ax^4+bx^2+x+5, where a and b are constants. Find f(4) if f(-4)=3.
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\n" ); document.write( "\n" ); document.write( "Let us write the fact that  f(-4) = 3.\r
\n" ); document.write( "\n" ); document.write( "Simply substitute  x = -4  into the given polynomial.  You will have\r
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\n" ); document.write( "\n" ); document.write( "f(-4) = \"a%2A%28-4%29%5E4+%2B+b%2A%28-4%29%5E2+%2B+%28-4%29+%2B+5\" = \"3\".\r
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\n" ); document.write( "\n" ); document.write( "Simplify it,  taking into account that  \"%28-4%29%5E4\" = \"4%5E4\"  and  \"%28-4%29%5E2\" = \"4%5E2\".  You will have \r
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\n" ); document.write( "\n" ); document.write( "f(-4) = \"a%2A4%5E4+%2B+b%2A4%5E2+%2B+%28-4%29+%2B+5\" = \"3\".         (1) \r
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\n" ); document.write( "\n" ); document.write( "Now express  f(4).  Simply substitute  x = 4  into the given polynomial.  You will get \r
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\n" ); document.write( "\n" ); document.write( "f(4) = \"a%2A4%5E4+%2B+b%2A4%5E2+%2B+4+%2B+5\".                     (2) \r
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\n" ); document.write( "\n" ); document.write( "Now compare expressions  (1)  and  (2).  They are almost identical.  The difference is in linear terms  (-4)  in   (1)  and  4  in  (2). \r
\n" ); document.write( "\n" ); document.write( "Hence,  f(4)  is in  8  units greater than  f(-4).  It means that  f(4) = f(-4) + 8 = 3 + 8 = 11.\r
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\n" ); document.write( "\n" ); document.write( "Answer.  f(4) = 11.\r
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