document.write( "Question 995490: A small business buys a computer for $4000. After 4 years the value of the computer is expected to be $200. For accounting purposes the business uses linear depreciation to assess the value of the computer at a given time. This means that if V is the value of the computer at time t, then a linear equation is used to relate V and t.
\n" ); document.write( "(a) Find a linear equation that relates V (in dollars) and t (in yr).\r
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\n" ); document.write( "\n" ); document.write( "(I keep getting confused on which comes first, v or t. Or how they relate to one another) \n" ); document.write( "
Algebra.Com's Answer #614258 by MathTherapy(10552)\"\" \"About 
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A small business buys a computer for $4000. After 4 years the value of the computer is expected to be $200. For accounting purposes the business uses linear depreciation to assess the value of the computer at a given time. This means that if V is the value of the computer at time t, then a linear equation is used to relate V and t.
\n" ); document.write( "(a) Find a linear equation that relates V (in dollars) and t (in yr).\r
\n" ); document.write( "\n" ); document.write( "(I keep getting confused on which comes first, v or t. Or how they relate to one another)
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V(t) signifies the value of the computer at a certain point in time (years)
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document.write( "Since the value of the computer is $200 in the 4th year, we can determine the ANNUAL DEPRECIATION (D) by saying that:
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document.write( "V(t) = 4,000 - Dt
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document.write( "V(4) = 4,000 - D(4) ---- Substituting 4 for t, in years
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document.write( " 200 = 4,000 - 4D ------ Substituting 200 for computer's value in the 4th year
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document.write( "  4D = 4,000 - 200
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document.write( "  4D = 3,800
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document.write( "D, or annual depreciation  = \"3800%2F4\", or $950
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document.write( "We now get the following equation: \"highlight_green%28V%28t%29+=+4000+-+950t%29\" \n" );
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