document.write( "Question 995453: 1)Draw the parabola with a zero at (3,0) ,a vertex at (3,0) and a y intercept of (0,8)\r
\n" ); document.write( "\n" ); document.write( "2)Draw the parabola with a minimum value of 2, an axis of symmetry of 3, no zeros, and a y intercept of 8.\r
\n" ); document.write( "\n" ); document.write( "3)Draw the parabola with a y intercept of 4, an axis of symmetry of 0, and no zeros.
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Algebra.Com's Answer #614210 by Boreal(15235)\"\" \"About 
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Vertex form is y= a(x-h)^2+k
\n" ); document.write( "for a
\n" ); document.write( "a(x-3)^2=y, since k=0
\n" ); document.write( "But (0,8) is a solution, so y=8 when x=0.
\n" ); document.write( "8=-(3)^2*a
\n" ); document.write( "9a=8
\n" ); document.write( "a=(8/9)
\n" ); document.write( "y=(8/9)(x^2-6x+9)
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%2864%2F81%29x%5E2-%2848%2F9%29x%2B%289%29%29\"
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\n" ); document.write( "minimum of 2 means the y-value of the vertex is 2.
\n" ); document.write( "axis of symmetry of 3 means the x value of the vertex is 3.
\n" ); document.write( "Therefore, the vertex is at (3,2)
\n" ); document.write( "y intercept is at 8.
\n" ); document.write( "To draw this, the vertex is at (3,2) and one point is at (0,8). Use the idea of symmetry to realize when x goes to the left 3, y goes up 6. When x goes to the right 3, y goes up 6. Your third point is (6,8). With those 3 points, you can draw the parabola.
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\n" ); document.write( "y-intercept of 4 means when x=0, y=4.
\n" ); document.write( "No zeros means this opens upward.
\n" ); document.write( "y=x^2+4. Note, with this one, y=ax^2+4, where a is positive, will work.
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