document.write( "Question 995453: 1)Draw the parabola with a zero at (3,0) ,a vertex at (3,0) and a y intercept of (0,8)\r
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document.write( "2)Draw the parabola with a minimum value of 2, an axis of symmetry of 3, no zeros, and a y intercept of 8.\r
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document.write( "3)Draw the parabola with a y intercept of 4, an axis of symmetry of 0, and no zeros.
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Algebra.Com's Answer #614210 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Vertex form is y= a(x-h)^2+k \n" ); document.write( "for a \n" ); document.write( "a(x-3)^2=y, since k=0 \n" ); document.write( "But (0,8) is a solution, so y=8 when x=0. \n" ); document.write( "8=-(3)^2*a \n" ); document.write( "9a=8 \n" ); document.write( "a=(8/9) \n" ); document.write( "y=(8/9)(x^2-6x+9) \n" ); document.write( " \n" ); document.write( "====================================== \n" ); document.write( "minimum of 2 means the y-value of the vertex is 2. \n" ); document.write( "axis of symmetry of 3 means the x value of the vertex is 3. \n" ); document.write( "Therefore, the vertex is at (3,2) \n" ); document.write( "y intercept is at 8. \n" ); document.write( "To draw this, the vertex is at (3,2) and one point is at (0,8). Use the idea of symmetry to realize when x goes to the left 3, y goes up 6. When x goes to the right 3, y goes up 6. Your third point is (6,8). With those 3 points, you can draw the parabola. \n" ); document.write( "=================================== \n" ); document.write( "y-intercept of 4 means when x=0, y=4. \n" ); document.write( "No zeros means this opens upward. \n" ); document.write( "y=x^2+4. Note, with this one, y=ax^2+4, where a is positive, will work. \n" ); document.write( " |