document.write( "Question 85226: Martina leaves home at 9 am bicycling at a rate of 24mi/h. Two hours later, John leaves driving at the rate of 48mi/h. At what time will John catch up with Martina? \n" ); document.write( "
Algebra.Com's Answer #61420 by stanbon(75887) ![]() You can put this solution on YOUR website! Martina leaves home at 9 am bicycling at a rate of 24mi/h. Two hours later, John leaves driving at the rate of 48mi/h. At what time will John catch up with Martina? \n" ); document.write( "------------- \n" ); document.write( "Martina DATA: \n" ); document.write( "Rate = 24 mph ; Time = x hrs ; Distance = rt =24x miles \n" ); document.write( "---------------- \n" ); document.write( "John DATA: \n" ); document.write( "Rate = 48 mph ; Time = x-2 hrs; Distance = rt = 48(x-2) mi \n" ); document.write( "----------------- \n" ); document.write( "EQUATION: \n" ); document.write( "distance = distance \n" ); document.write( "24x = 48(x-2) \n" ); document.write( "x=2x-4 \n" ); document.write( "x=4 hrs \n" ); document.write( "------------ \n" ); document.write( "9 AM + 4 hrs = 1:00 PM \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |