document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995450>Question 995450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Square root 75 plus square root 3x equals 4 rad 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614186 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(75)=sqrt(25)*sqrt(3)=5 sqrt (3)<BR>\n" );
document.write( "5 sqrt (3)+sqrt (3x)=4 sqrt(3)<BR>\n" );
document.write( "subtract 5 sqrt (3) from both sides<BR>\n" );
document.write( "sqrt(3x)= -sqrt (3)<BR>\n" );
document.write( "square both sides<BR>\n" );
document.write( "3x= (-3)<BR>\n" );
document.write( "x=-1<BR>\n" );
document.write( "==========<BR>\n" );
document.write( "Check to see if this is possible.<BR>\n" );
document.write( "5 sqrt(3) + sqrt (-3)=4 sqrt (3)<BR>\n" );
document.write( "sqrt (-3) does not exist in real system.<BR>\n" );
document.write( "no solution. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );