document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995416>Question 995416</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 50% juice is to be mixed witha 30% juice to get 200 liters of a 45% juice mixture how many liters of each must be mixed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614174 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a 50% juice is to be mixed witha 30% juice to get 200 liters of a 45% juice mixture how many liters of each must be mixed<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.50x + 0.30(200-x) = 0.45*200<BR>\n" );
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document.write( "50x + 30*200 - 30x = 45*200<BR>\n" );
document.write( "20x = 15*200<BR>\n" );
document.write( "x = (3/4)200<BR>\n" );
document.write( "x = 150 liters (amt. of 50% juice needed)<BR>\n" );
document.write( "200-x = 50 liters (amt. of 30% joice needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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