document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995366>Question 995366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this word problem:  The larger of the two numbers is 1 less than 3 times the smaller number if twice the smaller number is increased by the larger number the result is 18 more than the larger number .find both numbers  <BR>\n" );
document.write( "  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614115 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the larger number and y be the smaller number, then<BR>\n" );
document.write( "x = 3y -1<BR>\n" );
document.write( "2y +x = x + 18<BR>\n" );
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document.write( "use second equation<BR>\n" );
document.write( "subtract x from both sides of =<BR>\n" );
document.write( "2y = 18<BR>\n" );
document.write( "y = 9<BR>\n" );
document.write( "substitute for y in first equation<BR>\n" );
document.write( "x = 3*9 -1<BR>\n" );
document.write( "x = 26<BR>\n" );
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document.write( "the two numbers are 26 and 9<BR>\n" );
document.write( "check using second equation<BR>\n" );
document.write( "(2*9) +26 = 26 + 18<BR>\n" );
document.write( "18 = 18<BR>\n" );
document.write( "answer checks<BR>\n" );
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