document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995362>Question 995362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two digit number is 12. The tens digit is 2 less than the units digit. Find the number.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614110 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10x+y= 12<BR>\n" );
document.write( "10x= y-2 Let's go back to the first equation and plug in this value for 10x<BR>\n" );
document.write( "y-2+y= 12 Add 2 on both sides and ys on left<BR>\n" );
document.write( "2y= 14 Divide both sides by 2<BR>\n" );
document.write( "y= 7<BR>\n" );
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document.write( "The problem says:<BR>\n" );
document.write( "10x= y-2 And now we say that y= 7, so 10x= 7-2= 5. Now back to the first equation with these values:<BR>\n" );
document.write( "10(5)+7= 57 is your number. </SPAN>\n" );
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