document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995346>Question 995346</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that their sum deceased  by the second equals 50.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614105 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x, x+2, x+4 be three consecutive odd integers, then<BR>\n" );
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document.write( "Equation<BR>\n" );
document.write( "x +x+2 +x+4 -(x+2) = 50<BR>\n" );
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document.write( "Answer<BR>\n" );
document.write( "3x +6 -x -2 = 50<BR>\n" );
document.write( "2x +4 = 50<BR>\n" );
document.write( "2x = 46<BR>\n" );
document.write( "x = 23<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "23, 25, 27 is our answer<BR>\n" );
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document.write( "check answer<BR>\n" );
document.write( "23 +25 +27 -25 = 50<BR>\n" );
document.write( "23 + 27 = 50<BR>\n" );
document.write( "50 = 50<BR>\n" );
document.write( "our answer checks\r<BR>\n" );
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