document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995346>Question 995346</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that their sum deceased  by the second equals 50.<BR>\n" );
document.write( "Equation-_________<BR>\n" );
document.write( "Answer-__________ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614104 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+(x+2)+(x+2+2)-(x+2)= 50 Subtract the x+2s<BR>\n" );
document.write( "x+(x+2+2)= 50<BR>\n" );
document.write( "x+x+2+2= 50 Add on left<BR>\n" );
document.write( "2x+4= 50 Subtract 4 both sides<BR>\n" );
document.write( "2x = 46 Divide both sides by 2<BR>\n" );
document.write( "x= 23<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "23+25+27-25= 50<BR>\n" );
document.write( "23+27= 50<BR>\n" );
document.write( "50= 50 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );