document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995303>Question 995303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A point on the terminal side of an angle theta&#952; in standard position is left parenthesis 2 comma negative 4 right parenthesis(2,&#8722; 4). Find the exact value of each of the six trigonometric functions of theta&#952;. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614076 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A point on the terminal side of an angle theta&#952; in standard position is left parenthesis 2 comma negative 4 right parenthesis(2,&#8722; 4). Find the exact value of each of the six trigonometric functions of theta&#952;. <BR>\n" );
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document.write( "tan(t) = -4/2 = -2/1<BR>\n" );
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document.write( "Since tan = y/x, y = -2 and x = 1<BR>\n" );
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document.write( "Then r = sqrt(2^2+1^2) = sqrt(5)<BR>\n" );
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document.write( "sin = y/r = -2/sqrt(5)<BR>\n" );
document.write( "cos = x/r = 1/sqrt(5)<BR>\n" );
document.write( "tan = y/x = -2<BR>\n" );
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document.write( "csc = r/y = -sqrt(5)/2<BR>\n" );
document.write( "sec = r/x = sqrt(5)<BR>\n" );
document.write( "cot = x/y = -1/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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