document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995254>Question 995254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 240 L of a 60% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #614040 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=614040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "S=amount of 70% solution: T=amount of 30% solution<BR>\n" );
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document.write( "S+T=240L<BR>\n" );
document.write( "T=240L-S<BR>\n" );
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document.write( "(0.70)S+(0.30)T=(0.60)(240L)<BR>\n" );
document.write( "(0.70)S+(0.30)(240L-S)=144L<BR>\n" );
document.write( "0.70S+72L-0.30S=144L<BR>\n" );
document.write( "0.40S=72<BR>\n" );
document.write( "S=180L<BR>\n" );
document.write( "T=240L-S=240L-180L=60L<BR>\n" );
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document.write( "ANSWER: 180 liters of 70% solution mixed with 60 liters<BR>\n" );
document.write( "of 30% solution yields 240 liters of 60% solution.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
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document.write( "(0.70)S+(0.30)T=(0.60)(240L)<BR>\n" );
document.write( "(0.70)180L+(0.30)60L=(0.60)(240L)<BR>\n" );
document.write( "126L+18L=144L<BR>\n" );
document.write( "144L=144L<BR>\n" );
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document.write( " </SPAN>\n" );
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