document.write( "Question 85190: Find the equation for each of the following lines and graph it. (You can put them all on the same graph if you want but label them)
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document.write( " a. A line with a slope of -2 that goes through the point (1,-3)
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document.write( " b. A line with a slope of zero that passes through (2,-1)
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document.write( " c. A line with an undefined slope that passes through (-1,2)
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Algebra.Com's Answer #61404 by uma(370)![]() ![]() ![]() You can put this solution on YOUR website! a)Equation of a line with slope 'm' and through (x1,y1) is given by\r \n" ); document.write( "\n" ); document.write( " y-y1 = m(x-x1)\r \n" ); document.write( "\n" ); document.write( "==> y -(-3) = (-2)(x-1) \n" ); document.write( "==> y + 3 = -2x + 2 \n" ); document.write( "==> y = -2x + 2 - 3 \n" ); document.write( "==> y = -2x - 1 is the required equation.\r \n" ); document.write( "\n" ); document.write( "b) Slope = 0 and passes through (2,-1)\r \n" ); document.write( "\n" ); document.write( "==> y - (-1) = 0(x-2) \n" ); document.write( "==> y + 1 = 0 \n" ); document.write( "==> y = -1 is the required equation.\r \n" ); document.write( "\n" ); document.write( "c) Slope = undefined and passes through (-1,2)\r \n" ); document.write( "\n" ); document.write( "==> y - 2 = (1/0)(x-(-1))[undefined = 1/0]\r \n" ); document.write( "\n" ); document.write( "==> 0(y-2) = 1(x+1) \n" ); document.write( "==> 0 = x + 1 \n" ); document.write( "==> x = -1 is the required equation.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the above graph, the red line represents (a) and green line represents (b).(c) is not shown on the graph, but it is a line parallel to y axis and through x = -1(left of y axis)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( " |