document.write( "Question 12097: The sum of four consecutive odd intergers is 96.
\n" ); document.write( "Find the intergers. Must show Equation \n" ); document.write( "
Algebra.Com's Answer #6140 by bonster(299)\"\" \"About 
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there are 4 consecutive odd intergers. \r
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\n" ); document.write( "\n" ); document.write( "#1= x
\n" ); document.write( "#2= x+2
\n" ); document.write( "#3= x+4
\n" ); document.write( "#4= x+6\r
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\n" ); document.write( "\n" ); document.write( "the sum of these 4 intergers equals 96
\n" ); document.write( "x+(x+2)+(x+4)+(x+6)=96
\n" ); document.write( "4x+12=96 <--subtract 12 from both sides
\n" ); document.write( "4x+12-12=96-12
\n" ); document.write( "4x=84 <--divide both sides by 4
\n" ); document.write( "\"4x%2F4\"=\"84%2F4\"
\n" ); document.write( "x=21\r
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\n" ); document.write( "\n" ); document.write( "since#1=x and x=21, the first number is 21
\n" ); document.write( "x+2=21+2=23
\n" ); document.write( "x+4=21+4=25
\n" ); document.write( "x+6=27\r
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\n" ); document.write( "\n" ); document.write( "the four numbers are 21, 23, 25, 27 \r
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