document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=995160>Question 995160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy now one third as old as his father ,twelve years later he will be half as old as his father.then the present age of the boy is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613972 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A boy now one third as old as his father ,twelve years later he will be half as old as his father.then the present age of the boy is <BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "b = (1/3)f<BR>\n" );
document.write( "b+12 = (1/2)(f+12)<BR>\n" );
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document.write( "Substitute for \"b\" and solve for \"f\"::<BR>\n" );
document.write( "(1/3)f + 12 = (1/2)(f+12)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Multiply thru by 6 to get rid of the fractions::<BR>\n" );
document.write( "2f + 72 = 3(f+12)<BR>\n" );
document.write( "2f + 72 = 3f + 36<BR>\n" );
document.write( "----<BR>\n" );
document.write( "f = 36 (father's age now)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "boy = (1/3)f = 12 yrs<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "---------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );