document.write( "Question 995139: A student starting from his house walk at a speed of 2.5 km per hour and reaches his school 6 minute late. Next day at the same time he increases his speed by 1 km per hour and reaches 6 minute early. The distance between his school and house is?
\n" ); document.write( "A)3½ km
\n" ); document.write( "B)4 km
\n" ); document.write( "C)1¾ km
\n" ); document.write( "D)6 km \n" ); document.write( "
Algebra.Com's Answer #613956 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
t, time if arrival point is satisfied as normal time.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "                   speed     time        distance\r\n" );
document.write( "Trip late          2.5       t+1/10       d\r\n" );
document.write( "Trip early         3.5       t-1/10       d\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "The two unknowns in the system of equations are d and t.
\n" ); document.write( "\"system%28%282.5%29%28t%2B1%2F10%29=d%2C%283.5%29%28t-1%2F10%29=d%29\" \n" ); document.write( "
\n" );