document.write( "Question 995119: I really need help with this problem. Please show every step by step. Thank you\r
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\n" ); document.write( "\n" ); document.write( "The polynomial of degree 4, P(x)  has a root of multiplicity 2 at x=2  and roots of multiplicity 1 at x=0  and x=−2  . It goes through the point (5,252)  .
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Algebra.Com's Answer #613950 by ikleyn(52903)\"\" \"About 
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\n" ); document.write( "The polynomial of degree 4, P(x) has a root of multiplicity 2 at x=2 and roots of multiplicity 1 at x=0 and x=−2. It goes through the point (5,252).
\n" ); document.write( "Find a formula for P(x).
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\n" ); document.write( "\n" ); document.write( "According to the given information about the roots,  the polynomial is \r
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\n" ); document.write( "\n" ); document.write( "P(x) =  \"a%2A%28x-2%29%5E2%2A%28x-0%29%2A%28x-%28-2%29%29\" = \"a%2A%28x-2%29%5E2%2Ax%2A%28x%2B2%29\"           (1)\r
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\n" ); document.write( "\n" ); document.write( "with some unknown real coefficient  \"a\".\r
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\n" ); document.write( "\n" ); document.write( "To find  \"a\",  use the fact that the plot of the polynomial goes through the point  (5,252).  It means that  P(5) = 252. \r
\n" ); document.write( "\n" ); document.write( "So,  simply substitute  x=5  into the polynomial  (1). You will get the equation\r
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\n" ); document.write( "\n" ); document.write( "\"a%2A%285-2%29%5E2%2A5%2A%285%2B2%29\" = \"252\",     or\r
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\n" ); document.write( "\n" ); document.write( "\"a%2A3%5E2%2A5%2A7\" = \"252\",       or\r
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\n" ); document.write( "\n" ); document.write( "\"315a\" = \"252\".\r
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\n" ); document.write( "\n" ); document.write( "Hence,  \"a\" = \"252%2F315\" = \"4%2F5\".\r
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\n" ); document.write( "\n" ); document.write( "Therefore,  P(x) = \"4%2F5\".\"%28x-2%29%5E2%2Ax%2A%28x%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "You can open the parentheses if you need.\r
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