document.write( "Question 995055: If 1+2+3+...+50=1275, then 51+52+53+...+100=?
\n" ); document.write( "A. 1325
\n" ); document.write( "B. 2325
\n" ); document.write( "C. 3775
\n" ); document.write( "D. 63750
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Algebra.Com's Answer #613908 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"1%2B2%2B3\"+...+\"50=1275\", we can find the sum of these \"50\" numbers if we multiply half of the sum of first and last number by \"50\" like this:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%281%2B50%29%2F2%29%2A50=%2851%2F2%29%2A50=25.5%2A50=1275\"\r
\n" ); document.write( "\n" ); document.write( " then \"51%2B52%2B53\"+...+\"100\"= will be\r
\n" ); document.write( "\n" ); document.write( "\"%28%2851%2B100%29%2F2%29%2A50=%28151%2F2%2950=75.5%2A50=3775\"\r
\n" ); document.write( "\n" ); document.write( "so, answer is: C. \"3775\"
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