document.write( "Question 994953: Find a polynomial f(x), that has the degree of 4 or less, so
\n" ); document.write( "f(−2) = 0, f(−1) = 0, f(0) = 0, f(1) = 9, f(2) = 0.
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Algebra.Com's Answer #613848 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "According to the condition, your polynomial has the roots  -2,  -1,  0,  and  2.\r
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\n" ); document.write( "\n" ); document.write( "Hence,  the polynomial is \r
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\n" ); document.write( "\n" ); document.write( "f(x) = a*(x-(-2))*(x-(-1))*(x-0)*(x-2) = a*(x+2)*x+1)*x*(x-2), \r
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\n" ); document.write( "\n" ); document.write( "where  a  is a coefficient,  an unknown real number.\r
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\n" ); document.write( "\n" ); document.write( "To find  a,  use the condition  f(1) = 9. \r
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\n" ); document.write( "\n" ); document.write( "Simply substitute  x=1  into this equation  (into the polynomial).  You will get \r
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\n" ); document.write( "\n" ); document.write( "a*(1+2)*(1+1)*1*(1-2) = 9.\r
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\n" ); document.write( "\n" ); document.write( "Simplify the left side.  You will get a*3*2*1*(-1) = -6a.\r
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\n" ); document.write( "\n" ); document.write( "So,  the equation for  a  is\r
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\n" ); document.write( "\n" ); document.write( "-6a = 9.\r
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\n" ); document.write( "\n" ); document.write( "Hence,  a = \"-9%2F6\" = \"-3%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "Now your polynomial is \r
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\n" ); document.write( "\n" ); document.write( "f(x) = \"-3%2F2\"*(x+2)*x+1)*x*(x-2).\r
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