document.write( "Question 988971: How can you create a graph of y=2x-6 \n" ); document.write( "
Algebra.Com's Answer #613823 by EdenWolf(517)\"\" \"About 
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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=2%2Ax-6\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-1
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\n" ); document.write( " \"y=2%2A%28-1%29-6\"
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\n" ); document.write( " \"y=-2-6\" Multiply
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\n" ); document.write( " \"y=-8\" Add
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\n" ); document.write( " So here's one point (-1,-8)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=0
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\n" ); document.write( " \"y=2%2A%280%29-6\"
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\n" ); document.write( " \"y=0-6\" Multiply
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\n" ); document.write( " \"y=-6\" Add
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\n" ); document.write( " So here's another point (0,-6). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=2%2Ax-6\" through the points (-1,-8) and (0,-6)
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\n" ); document.write( " So from the graph we can see that the slope is \"2%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 1 units to get to the next point) the y-intercept is (0,\"-6\")and the x-intercept is (\"3\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=-6\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"-6\").
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\n" ); document.write( " So we have one point (0,\"-6\")
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\n" ); document.write( " Now since the slope is \"2%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"-6\"), we can go up 2 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=2%2Ax-6\"
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\n" ); document.write( " So this is the graph of \"y=2%2Ax-6\" through the points (0,-6) and (1,-4)
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