document.write( "Question 12099: Nicole has $3.15 in nickles, dimes and quarters. She has 3 more nickles than quarters and two times as many dimes as quarters. How many coins of each kind does she have? Show Equation. \n" ); document.write( "
Algebra.Com's Answer #6138 by bonster(299)\"\" \"About 
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she has 3 more nickles than quarters=x+3
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\n" ); document.write( "she has two times as many dimes as quarters=2x\r
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\n" ); document.write( "\n" ); document.write( "nickles: multiply (x+3)by (.05)
\n" ); document.write( "quarters: multiply (x) by (.25)
\n" ); document.write( "dimes: multiply 2x by .10\r
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\n" ); document.write( "\n" ); document.write( "(x+3)(.05)+(x)(.25)+(2x)(.10)=3.15
\n" ); document.write( "0.05x+0.15 +0.25x+0.20x=3.15
\n" ); document.write( "0.50x+0.15=3.15 <--subtract both sides by .15
\n" ); document.write( "(0.50x+0.15)-0.15=(3.15)-0.15
\n" ); document.write( "0.50x=3 <--divide both sides by .5
\n" ); document.write( "\"0.50x%2F.5\"=\"3%2F.5\"
\n" ); document.write( "x=6\r
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\n" ); document.write( "\n" ); document.write( "since quarters=x, and x=6 she has 6 quarters
\n" ); document.write( "nickles=x+3=6+3=9 nickles
\n" ); document.write( "dimes=2x=2(6)=12 dimes\r
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\n" ); document.write( "\n" ); document.write( "check: 6($0.25)+9($0.05)+12($0.10)
\n" ); document.write( "$1.50+$0.45+$1.20=$3.15
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