document.write( "Question 994795: On a right triangle with base measured as x, the side labled as x, and the hypotenuse unlabeled,and the perimeter of the triangle is 4+2square root2. What is the value of x? the answer choices are A) 2 B) 4 C) square root of 2 D) 2Square root2 and E) 2+2square root2. Can you please respond quickley and show work thanks. \n" ); document.write( "
Algebra.Com's Answer #613781 by rothauserc(4718)\"\" \"About 
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let h be the hypotenuse
\n" ); document.write( "h^2 = x^2 + x^2
\n" ); document.write( "h^2 = 2x^2
\n" ); document.write( "h = x * square root(2)
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\n" ); document.write( "x + x + (x*square root(2) = 4+2square root(2)
\n" ); document.write( "x * (2 + square root(2)) = 4 + 2square root(2)
\n" ); document.write( "x = (4 + 2square root(2)) / (2 + square root(2))
\n" ); document.write( "x = 2(2 + square root(2)) / (2 + square root(2))
\n" ); document.write( "x = 2
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\n" ); document.write( "answer is A) 2
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