document.write( "Question 994775: Ryan left the science museum and drove south. Gabriella left 3 hours later driving 42 km/h faster in an effort to catch up to him. After 2 hours Gabriella finally caught up. Find Ryan's average speed. \n" ); document.write( "
Algebra.Com's Answer #613777 by josgarithmetic(39621)\"\" \"About 
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document.write( "PERSON        speed        time        distance\r\n" );
document.write( "Ryan           r           3+2=5        r*5\r\n" );
document.write( "Garbiella     r+42         2            (r+42)*2\r\n" );
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\n" ); document.write( "\n" ); document.write( "The distance column is the \"catch-up\" distance, and each expression is the same quantity; the expressions are equal.\r
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\n" ); document.write( "\n" ); document.write( "\"r%2A5=%28r%2B42%29%2A2\"
\n" ); document.write( "\"5r=2r%2B84\"
\n" ); document.write( "\"3r=84\"
\n" ); document.write( "\"r=7%2A12%2F3\"
\n" ); document.write( "\"highlight%28r=28%29\"
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