document.write( "Question 994629: in a school x no of boys is 40 percent more than girls and in a school y no of girls is 50 percent more than boys if 50 percent of boys in school x =70 percent of girls in school y what is the ratio between no of students of school x and y? \n" ); document.write( "
Algebra.Com's Answer #613776 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! \"in a school x no of boys is 40 percent more than girls,\" \n" ); document.write( "lets try this with some values, \n" ); document.write( "let b = no. of boys in the x school \n" ); document.write( "let g = no. of girls \n" ); document.write( "x = 360 total students in x school \n" ); document.write( "then \n" ); document.write( "b + g = 360 \n" ); document.write( "given statement \n" ); document.write( "b = 1.4g \n" ); document.write( "Replace b with 1.4g \n" ); document.write( "1.4g + g = 360 \n" ); document.write( "2.4g = 360 \n" ); document.write( "g = 360/2.4 \n" ); document.write( "g = 150 girls in x school \n" ); document.write( "and \n" ); document.write( "360 - 150 = 210 boys in x school \n" ); document.write( ": \n" ); document.write( " if 50 percent of boys in school x = 70 percent of girls in school y, \n" ); document.write( "let f = no. of girls in school y \n" ); document.write( ".5(210) = .7f \n" ); document.write( "105 = .7f \n" ); document.write( "f = 105/.7 \n" ); document.write( "f = 50 girls in school y \n" ); document.write( ": \n" ); document.write( "It also says,\"in a school y no of girls is 50 percent more than boys.\" \n" ); document.write( "let m = no. of boys in school y \n" ); document.write( "1.5m = 50 \n" ); document.write( "m = 50/1.5 \n" ); document.write( "m = 150 boys in school y \n" ); document.write( ": \n" ); document.write( "Find the total students in school y \n" ); document.write( "50 + 150 = 200 \n" ); document.write( ":\ \n" ); document.write( " what is the ratio between no of students of school x and y? \n" ); document.write( " |