document.write( "Question 994764: It takes Erica, traveling at
\n" ); document.write( "24 mph,
\n" ); document.write( "50 minutes longer to go a certain distance than it takes Ricky traveling at
\n" ); document.write( "54 mph. Find the distance traveled.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #613769 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
It takes Erica, traveling at 24 mph, 50 minutes longer to go a certain distance han it takes Ricky traveling at 54 mph. Find the distance traveled.
\n" ); document.write( "----------
\n" ); document.write( "Erica DATA::
\n" ); document.write( "rate = 24 mph ; distance = x miles ; time = x/24 hrs
\n" ); document.write( "-------------------
\n" ); document.write( "Ricky DATA:
\n" ); document.write( "rate = 54 mph ; distance = x miles ; time = x/54 hrs
\n" ); document.write( "---------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "Erica time - Ricky time = (5/6) hr.
\n" ); document.write( "----
\n" ); document.write( "x/24 - x/54 = 5/6
\n" ); document.write( "-----
\n" ); document.write( "Multiply thru by 6 to get:
\n" ); document.write( "x/4 - x/9 = 5
\n" ); document.write( "-----
\n" ); document.write( "9x - 4x = 5*4*9
\n" ); document.write( "----
\n" ); document.write( "5x = 5*4*9
\n" ); document.write( "x = 36 miles
\n" ); document.write( "----
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "---------
\n" ); document.write( "
\n" ); document.write( "
\n" );