document.write( "Question 994720:  a waitress sold 17 ribeye steak dinners and 20 grilled salmon dinners, totalling $590.81 on a particular day. Another day she sold 24 ribeye steak dinners and 10 grilled salmon dinners, totaling $580.66. How much did each type of dinner cost? \n" ); document.write( "
Algebra.Com's Answer #613744 by macston(5194)\"\" \"About 
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\n" ); document.write( "R=cost of rib-eye dinner; S=cost of salmon dinner
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\n" ); document.write( "24R+10S=$580.66
\n" ); document.write( "10S=$580.66-24R
\n" ); document.write( "20S=$1161.32-48R Use this to substitute for 20S below
\n" ); document.write( ".
\n" ); document.write( "17R+20S=$590.81 . Substitute for 20S.
\n" ); document.write( "17R+($1161.32-48R)=$590.81
\n" ); document.write( "-31R=-$570.51
\n" ); document.write( "R=$18.40
\n" ); document.write( "ANSWER 1: Rib-eye dinner costs $18.40.
\n" ); document.write( ".
\n" ); document.write( "24R+10S=$580.66
\n" ); document.write( "24($18.40)+10S=$580.66
\n" ); document.write( "$441.60+10S=$580.66 441.69
\n" ); document.write( "10S=$139.06
\n" ); document.write( "S=$13.91
\n" ); document.write( "ANSWER 2: A salmon dinner costs $13.91.
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( ".
\n" ); document.write( "17R+20S=$590.81
\n" ); document.write( "17($18.40)+20($13.91)=$590.81
\n" ); document.write( "$312.80+$278.20=$590.81
\n" ); document.write( "$591=$590.81
\n" ); document.write( "19 cent discrepancy from rounding to nearest cent.\r
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