document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994699>Question 994699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need your help with this word problem :(\r<BR>\n" );
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document.write( "A motor scooter travels 16 mi in the same time that a bicycle covers 7 mi. If the rate of the scooter is 5mph more than twice the rate of the bicycle, find both rates. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613721 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613721\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> bicycle rate is x mph<BR>\n" );
document.write( "scooter rate is 2x+5 mph<BR>\n" );
document.write( "2x+5 mph * y hours=16 mi.<BR>\n" );
document.write( "y=16/(2x+5)<BR>\n" );
document.write( "also<BR>\n" );
document.write( "x mph * y hours=7 miles<BR>\n" );
document.write( "y=7/x.<BR>\n" );
document.write( "So, (16/(2x+5))=(7/x)<BR>\n" );
document.write( "cross multiply<BR>\n" );
document.write( "16x=7(2x+5)<BR>\n" );
document.write( "16x=14x+35<BR>\n" );
document.write( "2x=35<BR>\n" );
document.write( "x=17.5 mph bicycle<BR>\n" );
document.write( "2x+5=40 mph scooter<BR>\n" );
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document.write( "scooter travels 16 miles at 40 mph, that is 0.4 hours or 24 minutes.<BR>\n" );
document.write( "bicycle travels 7 miles at 17.5 mph, that is 7/17.5 hours, and that is 0.4 hours or 24 minutes. </SPAN>\n" );
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