document.write( "Question 994670: ten years ago a father was six time as old as his son. After 10 years, he will be twice as old as his son. determine their present ages. \n" ); document.write( "
Algebra.Com's Answer #613698 by stanbon(75887)\"\" \"About 
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ten years ago a father was six time as old as his son. After 10 years, he will be twice as old as his son. determine their present ages.
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\n" ); document.write( "Equations:
\n" ); document.write( "f-10 = 6(s-10)
\n" ); document.write( "f+10 = 2(s+10)
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\n" ); document.write( "Rearrange::
\n" ); document.write( "f - 6s = -50
\n" ); document.write( "f - 2s = 10
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\n" ); document.write( "Subtract and solve for \"s\"::
\n" ); document.write( "4s = 40
\n" ); document.write( "s = 10 yrs (son's age now)
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\n" ); document.write( "Solve for \"f\":
\n" ); document.write( "f - 2s = 10
\n" ); document.write( "f-20 = 10
\n" ); document.write( "f = 30 yrs (father's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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