document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994659>Question 994659</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first term of an arithmetic sequence is equal to 6 and the common difference is equal to 3. Find the formula for the nth term and the value of the 50th term . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613681 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first term of an arithmetic sequence is equal to 6 and the common difference is equal to 3. Find the formula for the nth term and the value of the 50th term . <BR>\n" );
document.write( "---<BR>\n" );
document.write( "a(n) = 6 + (n-1)3<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "a(50) = 6 + 49*3 = 153<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );