document.write( "Question 994597: Separate 132 into two parts such that if the larger is divided by the smaller. The quotient is 6 and the remainder is 13. \n" ); document.write( "

Algebra.Com's Answer #613627 by KMST(5328) $\"\"$ $\"About$

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$\"x\"$ = the smaller part
\n" ); document.write( " $\"132-x\"$ = the larger part
\n" ); document.write( "If the larger part, $\"132-x\"$ , is divided by the smaller, $\"x\"$ , the quotient is 6 and the remainder is 13
\n" ); document.write( "means that $\"132-x\"$ , minus the $\"13\"$ remainder, divided by $\"x\"$ is exactly $\"6\"$ :
\n" ); document.write( " $\"6=%28132-x-13%29%2Fx\"$
\n" ); document.write( "Solving:
\n" ); document.write( " $\"6=%28132-x-13%29%2Fx\"$ --> $\"6=%28119-x%29%2Fx\"$ --> $\"6x=119-x\"$ --> $\"6x%2Bx=119\"$ --> $\"7x=119\"$ --> $\"x=119%2F7\"$ --> $\"highlight%28x=17%29\"$ .
\n" ); document.write( "Then $\"132-x=132-17\"$ --> $\"highlight%28132-x=115%29\"$
\n" ); document.write( "The two parts are $\"highlight%2817%29\"$ and $\"highlight%28115%29\"$ . \n" ); document.write( "

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