document.write( "Question 994497: If I am riding a bike at 18 mph and my friend is riding 3 miles ahead at 12 mph. How long before I catch up to him? \n" ); document.write( "
Algebra.Com's Answer #613556 by josmiceli(19441)\"\" \"About 
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Let \"+d+\" = distance in miles you travel
\n" ); document.write( "until you catch friend
\n" ); document.write( "Let \"+t+\" = time in hours it takes you
\n" ); document.write( "to catch friend
\n" ); document.write( "-----------------------
\n" ); document.write( "Friend's equation:
\n" ); document.write( "(1) \"+d+-+3+=+12t+\"
\n" ); document.write( "Your equation:
\n" ); document.write( "(2) \"+d+=+18t+\"
\n" ); document.write( "-----------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+18t+-+3+=+12t+\"
\n" ); document.write( "(1) \"+6t+=+3+\"
\n" ); document.write( "(1) \"+t+=+1%2F2+\"
\n" ); document.write( "---------------
\n" ); document.write( "You will catch friend in 1/2 hr
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+18%2A%281%2F2%29+\"
\n" ); document.write( "(2) \"+d+=+9+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+-+3+=+12%2A%281%2F2%29+\"
\n" ); document.write( "(1) \"+d+-+3+=+6+\"
\n" ); document.write( "(1) \"+d+=+9+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );