document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=85076>Question 85076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 94 inches: its length is 2 inches more than twice its width.  Find the length of width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61354 by </B><A HREF=/tutors/aboutme.mpl?userid=mala_kumarkos@yahoo.com><B>mala_kumarkos@yahoo.com(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mala_kumarkos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   <BR>\n" );
document.write( "    perimeter of a rectangle is=94 inches<BR>\n" );
document.write( "     width be= x inches<BR>\n" );
document.write( "      length = 2x+2 inches<BR>\n" );
document.write( "      perimeter = 2(l+w)<BR>\n" );
document.write( "        94= 2(2x+2+x)<BR>\n" );
document.write( "        47 = 3x+2<BR>\n" );
document.write( "        47-2= 3x<BR>\n" );
document.write( "        45 = 3x<BR>\n" );
document.write( " therefore x = 45/3 =15   width = 15 inches  and length = 32 inches. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );