document.write( "Question 85127: What is the domain of f(x)= 6x+5/x+5 \n" ); document.write( "
Algebra.Com's Answer #61350 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Since we cannot divide by zero, we can find exclusions in the domain by setting the denominator equal to zero and solving for x:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since x=-5 makes the denominator equal to zero, we must exclude -5 from our domain. So our domain is: x is the set of all real numbers, except x cannot equal -5. Basically we can choose any number we want, except -5, and plug it in for x to get a real number output.\r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "In interval notation, the domain would look like this:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice when we graph the equation \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and you can see that x=-5 is not part of the domain (note: the vertical line is not part of the graph, it is an asymptote)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |