document.write( "Question 994422: Find two consecutive even integers such that four times the first plus two times the second is 40 \n" ); document.write( "
Algebra.Com's Answer #613499 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Lets call the first integer \"x\", and the second integer is to be a consecutive even integer, so it must be \"x%2B2\"\r
\n" ); document.write( "\n" ); document.write( "if four times the first plus two times the second is \"40\", we have\r
\n" ); document.write( "\n" ); document.write( "\"4%2Ax%2B2%28x%2B2%29=40\"...solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%2B2x%2B4=40\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=40-4\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=36\"\r
\n" ); document.write( "\n" ); document.write( "\"x=36%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=6%29\"=>the first integer\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2=6%2B2\"=>\"highlight%28x%2B2=8%29\"=>the second integer\r
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