document.write( "Question 994397: A woman can bicycle 92 miles in the same time as it takes her to walk 20 miles. She can ride 9 mph faster than she can walk. How fast can she walk?\r
\n" ); document.write( "\n" ); document.write( "Using r as your variable to represent the rate at which she walks, write an equation using the information as it is given above that can be used to solve this problem.\r
\n" ); document.write( "\n" ); document.write( "What's the equation needed to solve this problem?\r
\n" ); document.write( "\n" ); document.write( "How many mph does she walk?
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Algebra.Com's Answer #613495 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A woman can bicycle 92 miles in the same time as it takes her to walk 20 miles. She can ride 9 mph faster than she can walk. How fast can she walk?
\n" ); document.write( "Using r as your variable to represent the rate at which she walks, write an equation using the information as it is given above that can be used to solve this problem.
\n" ); document.write( "What's the equation needed to solve this problem?
\n" ); document.write( "How many mph does she walk?
\n" ); document.write( "------
\n" ); document.write( "Biking DATA:
\n" ); document.write( "dist = 92 miles ; rate = x+9 mph ; time = d/r = 92/(x+9) hrs
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\n" ); document.write( "Walking DATA:
\n" ); document.write( "dist = 20 miles ; rate = x mph ; time = d/r = 20/x hrs
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\n" ); document.write( "Equations:
\n" ); document.write( "time = time
\n" ); document.write( "92/(x+9) = 20/x
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\n" ); document.write( "92x = 20(x+9)
\n" ); document.write( "92x = 20x + 180
\n" ); document.write( "72x = 180
\n" ); document.write( "x = 2.5 mph (walking)
\n" ); document.write( "x+9 = 11.5 mph (biking)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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