document.write( "Question 994397: A woman can bicycle 92 miles in the same time as it takes her to walk 20 miles. She can ride 9 mph faster than she can walk. How fast can she walk?\r
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document.write( "Using r as your variable to represent the rate at which she walks, write an equation using the information as it is given above that can be used to solve this problem.\r
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document.write( "What's the equation needed to solve this problem?\r
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document.write( "How many mph does she walk? \n" );
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Algebra.Com's Answer #613495 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A woman can bicycle 92 miles in the same time as it takes her to walk 20 miles. She can ride 9 mph faster than she can walk. How fast can she walk? \n" ); document.write( "Using r as your variable to represent the rate at which she walks, write an equation using the information as it is given above that can be used to solve this problem. \n" ); document.write( "What's the equation needed to solve this problem? \n" ); document.write( "How many mph does she walk? \n" ); document.write( "------ \n" ); document.write( "Biking DATA: \n" ); document.write( "dist = 92 miles ; rate = x+9 mph ; time = d/r = 92/(x+9) hrs \n" ); document.write( "----------------- \n" ); document.write( "Walking DATA: \n" ); document.write( "dist = 20 miles ; rate = x mph ; time = d/r = 20/x hrs \n" ); document.write( "--------------- \n" ); document.write( "Equations: \n" ); document.write( "time = time \n" ); document.write( "92/(x+9) = 20/x \n" ); document.write( "----- \n" ); document.write( "92x = 20(x+9) \n" ); document.write( "92x = 20x + 180 \n" ); document.write( "72x = 180 \n" ); document.write( "x = 2.5 mph (walking) \n" ); document.write( "x+9 = 11.5 mph (biking) \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------- \n" ); document.write( " |