document.write( "Question 994364: how many liters of a 20% solution of a chemical should be mixed with 10 liters of a 50% solution to obtain a mixture that is 40% chemical \n" ); document.write( "
Algebra.Com's Answer #613494 by stanbon(75887)\"\" \"About 
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how many liters of a 20% solution of a chemical should be mixed with 10 liters of a 50% solution to obtain a mixture that is 40% chemical
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\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.20x + 0.50*10 = 0.40(x+10)
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\n" ); document.write( "20x + 50*10 = 40x + 40*10
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\n" ); document.write( "-20x = -10*10
\n" ); document.write( "x = 5 liters (amt. of 20% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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