document.write( "Question 994364: how many liters of a 20% solution of a chemical should be mixed with 10 liters of a 50% solution to obtain a mixture that is 40% chemical \n" ); document.write( "
Algebra.Com's Answer #613494 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many liters of a 20% solution of a chemical should be mixed with 10 liters of a 50% solution to obtain a mixture that is 40% chemical \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "active + active = active \n" ); document.write( "0.20x + 0.50*10 = 0.40(x+10) \n" ); document.write( "------- \n" ); document.write( "20x + 50*10 = 40x + 40*10 \n" ); document.write( "------- \n" ); document.write( "-20x = -10*10 \n" ); document.write( "x = 5 liters (amt. of 20% solution needed) \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |