document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994380>Question 994380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been trying to solve the following linear equation<BR>\n" );
document.write( "3X-5Y=11<BR>\n" );
document.write( "2x-6y=2\r<BR>\n" );
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document.write( "I keep getting the wrong answer so when I checked with you guys I noticed that it was substituted with 2(11-5y)/3-6y=2\r<BR>\n" );
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document.write( "I understand the substitution part but how do I solve from here what does the / mean next to the 3 what operation I'm suppose to there, I'm confused please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613476 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x -5y = 11<BR>\n" );
document.write( "2x -6y = 2 <BR>\n" );
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document.write( "solve second equation for x<BR>\n" );
document.write( "add 6y to both sides of =<BR>\n" );
document.write( "2x = 6y + 2<BR>\n" );
document.write( "divide both sides of = by 2<BR>\n" );
document.write( "x = 3y + 1<BR>\n" );
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document.write( "now substitute for x in first equation<BR>\n" );
document.write( "3(3y + 1) - 5y = 11<BR>\n" );
document.write( "9y + 3 - 5y = 11<BR>\n" );
document.write( "4y + 3 = 11<BR>\n" );
document.write( "subtract 3 from both sides of =<BR>\n" );
document.write( "4y = 8<BR>\n" );
document.write( "divide both sides of = by 4<BR>\n" );
document.write( "y = 2<BR>\n" );
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document.write( "substitute for y in first equation<BR>\n" );
document.write( "3x - 5(2) = 11<BR>\n" );
document.write( "3x - 10 = 11<BR>\n" );
document.write( "add 10 to both sides of =<BR>\n" );
document.write( "3x = 21<BR>\n" );
document.write( "divide both sides of = by 3<BR>\n" );
document.write( "x = 7<BR>\n" );
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document.write( "solution is x = 7 and y = 2<BR>\n" );
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document.write( "check this solution by substituting the solution in the second equation<BR>\n" );
document.write( "2(7) -6(2) = 2<BR>\n" );
document.write( "14 - 12 = 2<BR>\n" );
document.write( "2 = 2<BR>\n" );
document.write( "our solution checks<BR>\n" );
document.write( " <BR>\n" );
document.write( " </SPAN>\n" );
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