document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994380>Question 994380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been trying to solve the following linear equation<BR>\n" );
document.write( "3X-5Y=11<BR>\n" );
document.write( "2x-6y=2\r<BR>\n" );
document.write( "\n" );
document.write( "I keep getting the wrong answer so when I checked with you guys I noticed that it was substituted with 2(11-5y)/3-6y=2\r<BR>\n" );
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document.write( "I understand the substitution part but how do I solve from here what does the / mean next to the 3 what operation I'm suppose to there, I'm confused please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613475 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have been trying to solve the following linear equation<BR>\n" );
document.write( "3X-5Y=11<BR>\n" );
document.write( "2x-6y=2 divide by 2 --> x - 3y = 1 --> x = 3y + 1<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Sub for x in the 1st eqn<BR>\n" );
document.write( "3X-5Y=11<BR>\n" );
document.write( "3(3y+1) - 5y = 11<BR>\n" );
document.write( "9y+3 - 5y = 11<BR>\n" );
document.write( "4y = 8<BR>\n" );
document.write( "y = 2<BR>\n" );
document.write( "------<BR>\n" );
document.write( "x = 3y + 1<BR>\n" );
document.write( "x = 7\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );