document.write( "Question 994352: A is 7 year older to B. 15 years ago B's age was three fourth of A's age. Find their ages in years now \n" ); document.write( "
Algebra.Com's Answer #613460 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A is 7 year older to B. 15 years ago B's age was three fourth of A's age. Find their ages in years now \n" ); document.write( "---- \n" ); document.write( "Equations: \n" ); document.write( "A = B + 7 \n" ); document.write( "B-15 = (3/4)(A-15) \n" ); document.write( "---- \n" ); document.write( "Substitute for \"A\" and solve for \"B\": \n" ); document.write( "B-15 = (3/4)(B+7-15) \n" ); document.write( "----- \n" ); document.write( "4(B-15) = 3(B-8) \n" ); document.write( "4B-60 = 3B-24 \n" ); document.write( "B = 36 yrs (B's age now) \n" ); document.write( "--- \n" ); document.write( "A = B + 7 = 43 yrs (A's age now)\r \n" ); document.write( "\n" ); document.write( "-------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------- \n" ); document.write( " |