document.write( "Question 994352: A is 7 year older to B. 15 years ago B's age was three fourth of A's age. Find their ages in years now \n" ); document.write( "
Algebra.Com's Answer #613460 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A is 7 year older to B. 15 years ago B's age was three fourth of A's age. Find their ages in years now
\n" ); document.write( "----
\n" ); document.write( "Equations:
\n" ); document.write( "A = B + 7
\n" ); document.write( "B-15 = (3/4)(A-15)
\n" ); document.write( "----
\n" ); document.write( "Substitute for \"A\" and solve for \"B\":
\n" ); document.write( "B-15 = (3/4)(B+7-15)
\n" ); document.write( "-----
\n" ); document.write( "4(B-15) = 3(B-8)
\n" ); document.write( "4B-60 = 3B-24
\n" ); document.write( "B = 36 yrs (B's age now)
\n" ); document.write( "---
\n" ); document.write( "A = B + 7 = 43 yrs (A's age now)\r
\n" ); document.write( "\n" ); document.write( "--------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "--------
\n" ); document.write( "
\n" );