document.write( "Question 994283: One type of chocolate mixture contains 30% of nuts, by mass. A second type of chocolate mixture contains 20% of nuts, by mass. What mass of each type of chocolate mixture needs to be mixed to make a 500-g chocolate mixture that will have 24% nuts, by mass? \n" ); document.write( "

Algebra.Com's Answer #613455 by josgarithmetic(39618) $\"\"$ $\"About$

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y, mass to use of the 30% mixture
\n" ); document.write( "500-y, mass to use of the 20% nuts mixture\r
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\n" ); document.write( "\n" ); document.write( "Want mixture result to be 24%.
\n" ); document.write( " $\"%28%28500-y%29%2A20%2B30%2Ay%29%2F500=24\"$ \r
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\n" ); document.write( "\n" ); document.write( "A Helpful Example, video \n" ); document.write( "

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