document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994300>Question 994300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a backyard is 560 feet. If the width is 125 feet less than the length, find the length of the yard. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613447 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is: 2L+2W= 560 (1st formula)<BR>\n" );
document.write( "And the problem says that:<BR>\n" );
document.write( "W= L-125 Now apply the first formula using this value for W:<BR>\n" );
document.write( "2L+2(L-125)= 560 Multiply on left<BR>\n" );
document.write( "2L+2L-250= 560 Add L on left and add 250 to both sides:<BR>\n" );
document.write( "4L= 810 Divide both sides by 4<BR>\n" );
document.write( "L= 202.5 OK, we have our Length. And the problem says that the Width is 202.5-125= 77.5. Let's prove that we have the correct answer:<BR>\n" );
document.write( "2L+2W= 560<BR>\n" );
document.write( "2(202.5)+2(77.5)= 560<BR>\n" );
document.write( "405+155= 560 <BR>\n" );
document.write( "560= 560 We have the right answer. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );