document.write( "Question 994253: Find the point with coordinates of the form (a, 3a) that is in the third quadrant and is a distance 5 from
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Algebra.Com's Answer #613430 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Look for the negative value for a.\r
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\n" ); document.write( "\n" ); document.write( "Distance Formula, \"sqrt%28%28a-2%29%5E2%2B%283a-1%29%5E2%29=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2-4a%2B4%2B9a%5E2-6a%2B1=25\"\r
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\n" ); document.write( "\n" ); document.write( "\"10a%5E2-10a%2B5=25\"\r
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\n" ); document.write( "\n" ); document.write( "\"10%28a%5E2-a%29=20\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2-a=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2-a-2=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28a%2B1%29%28a-2%29=0\"
\n" ); document.write( "a=-1 will put the coordinates into quadrant #3, to be point (-1,-3).\r
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\n" ); document.write( "\n" ); document.write( "The other solution of a=2 will not be in quadrant #3.
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