document.write( "Question 994245:
\n" ); document.write( " _4_
\n" ); document.write( "-6+3(2)-1=? The 4 goes over the 3(2) in fraction form..\r
\n" ); document.write( "\n" ); document.write( " _4_ _2_
\n" ); document.write( "I worked it and got to -6+ 6 -1 = -6+ 3 -1
\n" ); document.write( "The 4 goes over the +6 and the 2 goes over the +3 in fraction form. Not sure if you can see it like I typed it. I apologize.
\n" ); document.write( "But I can't figure out if I'm doing that right and where to go from there
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Algebra.Com's Answer #613418 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "if the \"4\" goes over the \"6\" and the \"2\" goes over the \"3\" in fraction form, we have\r
\n" ); document.write( "\n" ); document.write( "\"4%2F6%2B2%2F3-1\"...simplify \"4%2F6\", divide both numerator and denominator by \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%284%292%2Fcross%286%293%2B2%2F3-1\"....write \"1\" as \"3%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2F3%2B2%2F3-3%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2B2-3%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"%284-3%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"1%2F3\"
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